Base | Representation |
---|---|
bin | 10001100110111111101… |
… | …001010111001010011101 |
3 | 11021200111000201012220012 |
4 | 101212333221113022131 |
5 | 124311241340214323 |
6 | 2323525054133005 |
7 | 153266301434504 |
oct | 21467751271235 |
9 | 4250430635805 |
10 | 1210101101213 |
11 | 427223584a24 |
12 | 1766384b1165 |
13 | 8a15c212c84 |
14 | 427d7c8783b |
15 | 217268b9678 |
hex | 119bfa5729d |
1210101101213 has 2 divisors, whose sum is σ = 1210101101214. Its totient is φ = 1210101101212.
The previous prime is 1210101101207. The next prime is 1210101101269. The reversal of 1210101101213 is 3121011010121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1107171137284 + 102929963929 = 1052222^2 + 320827^2 .
It is a cyclic number.
It is not a de Polignac number, because 1210101101213 - 210 = 1210101100189 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210101101203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605050550606 + 605050550607.
It is an arithmetic number, because the mean of its divisors is an integer number (605050550607).
Almost surely, 21210101101213 is an apocalyptic number.
It is an amenable number.
1210101101213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210101101213 is an equidigital number, since it uses as much as digits as its factorization.
1210101101213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 1210101101213 its reverse (3121011010121), we get a palindrome (4331112111334).
The spelling of 1210101101213 in words is "one trillion, two hundred ten billion, one hundred one million, one hundred one thousand, two hundred thirteen".
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