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12101012153 is a prime number
BaseRepresentation
bin10110100010100011…
…01100101010111001
31011020100012002222022
423101101230222321
5144240324342103
65320434404225
7605605622546
oct132121545271
934210162868
1012101012153
11514a78459a
122418730675
1311ab070c29
1482b1d3bcd
154ac575138
hex2d146cab9

12101012153 has 2 divisors, whose sum is σ = 12101012154. Its totient is φ = 12101012152.

The previous prime is 12101012129. The next prime is 12101012179. The reversal of 12101012153 is 35121010121.

12101012153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8047525264 + 4053486889 = 89708^2 + 63667^2 .

It is a cyclic number.

It is not a de Polignac number, because 12101012153 - 26 = 12101012089 is a prime.

It is not a weakly prime, because it can be changed into another prime (12101012113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050506076 + 6050506077.

It is an arithmetic number, because the mean of its divisors is an integer number (6050506077).

Almost surely, 212101012153 is an apocalyptic number.

It is an amenable number.

12101012153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101012153 is an equidigital number, since it uses as much as digits as its factorization.

12101012153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 12101012153 its reverse (35121010121), we get a palindrome (47222022274).

The spelling of 12101012153 in words is "twelve billion, one hundred one million, twelve thousand, one hundred fifty-three".