12101013132333 has 4 divisors (see below), whose sum is σ = 16134684176448. Its totient is φ = 8067342088220.

The previous prime is 12101013132331. The next prime is 12101013132337. The reversal of 12101013132333 is 33323131010121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12101013132333 - 2¹ = 12101013132331 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12101013132331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2016835522053 + ... + 2016835522058.

It is an arithmetic number, because the mean of its divisors is an integer number (4033671044112).

Almost surely, 2^{12101013132333} is an apocalyptic number.

It is an amenable number.

12101013132333 is a deficient number, since it is larger than the sum of its proper divisors (4033671044115).

12101013132333 is an equidigital number, since it uses as much as digits as its factorization.

12101013132333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4033671044114.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 12101013132333 its reverse (33323131010121), we get a palindrome (45424144142454).

It can be divided in two parts, 1210101 and 3132333, that added together give a palindrome (4342434).

The spelling of 12101013132333 in words is "twelve trillion, one hundred one billion, thirteen million, one hundred thirty-two thousand, three hundred thirty-three".