Base | Representation |
---|---|
bin | 10001100110111111101… |
… | …100110101010010001111 |
3 | 11021200111002102102220212 |
4 | 101212333230311102033 |
5 | 124311242103323043 |
6 | 2323525125433035 |
7 | 153266312244143 |
oct | 21467754652217 |
9 | 4250432372825 |
10 | 1210102011023 |
11 | 427224046534 |
12 | 17663886b77b |
13 | 8a15c471119 |
14 | 427d8043223 |
15 | 217269e9018 |
hex | 119bfb3548f |
1210102011023 has 4 divisors (see below), whose sum is σ = 1221411375720. Its totient is φ = 1198792646328.
The previous prime is 1210102011017. The next prime is 1210102011071. The reversal of 1210102011023 is 3201102010121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1210102011023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1210102010989 and 1210102011007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1210102011073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5654682188 + ... + 5654682401.
It is an arithmetic number, because the mean of its divisors is an integer number (305352843930).
Almost surely, 21210102011023 is an apocalyptic number.
1210102011023 is a deficient number, since it is larger than the sum of its proper divisors (11309364697).
1210102011023 is a wasteful number, since it uses less digits than its factorization.
1210102011023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11309364696.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1210102011023 its reverse (3201102010121), we get a palindrome (4411204021144).
The spelling of 1210102011023 in words is "one trillion, two hundred ten billion, one hundred two million, eleven thousand, twenty-three".
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