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1210111000997 is a prime number
BaseRepresentation
bin10001100111000000001…
…111001000000110100101
311021200111201100011211212
4101213000033020012211
5124311301404012442
62323530050241205
7153266451536033
oct21470017100645
94250451304755
101210111000997
11427229126868
1217663b886205
138a16129b032
14427d9303553
15217276c2a82
hex119c03c81a5

1210111000997 has 2 divisors, whose sum is σ = 1210111000998. Its totient is φ = 1210111000996.

The previous prime is 1210111000957. The next prime is 1210111001023. The reversal of 1210111000997 is 7990001110121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1194093820516 + 16017180481 = 1092746^2 + 126559^2 .

It is an emirp because it is prime and its reverse (7990001110121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1210111000997 - 26 = 1210111000933 is a prime.

It is a super-2 number, since 2×12101110009972 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1210111000957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605055500498 + 605055500499.

It is an arithmetic number, because the mean of its divisors is an integer number (605055500499).

Almost surely, 21210111000997 is an apocalyptic number.

It is an amenable number.

1210111000997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210111000997 is an equidigital number, since it uses as much as digits as its factorization.

1210111000997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1134, while the sum is 32.

The spelling of 1210111000997 in words is "one trillion, two hundred ten billion, one hundred eleven million, nine hundred ninety-seven", and thus it is an aban number.