12101112020021 has 4 divisors (see below), whose sum is σ = 12101811564000. Its totient is φ = 12100412476044.

The previous prime is 12101112019999. The next prime is 12101112020047. The reversal of 12101112020021 is 12002021110121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12101112020021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12101112019978 and 12101112020005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12101112029021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 349746041 + ... + 349780638.

It is an arithmetic number, because the mean of its divisors is an integer number (3025452891000).

Almost surely, 2^{12101112020021} is an apocalyptic number.

It is an amenable number.

12101112020021 is a deficient number, since it is larger than the sum of its proper divisors (699543979).

12101112020021 is an equidigital number, since it uses as much as digits as its factorization.

12101112020021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 699543978.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 12101112020021 its reverse (12002021110121), we get a palindrome (24103133130142).

The spelling of 12101112020021 in words is "twelve trillion, one hundred one billion, one hundred twelve million, twenty thousand, twenty-one".