Base | Representation |
---|---|
bin | 10001100111000000010… |
… | …011000001001000000001 |
3 | 11021200111210021000000111 |
4 | 101213000103001020001 |
5 | 124311302134132433 |
6 | 2323530124151321 |
7 | 153266463314551 |
oct | 21470023011001 |
9 | 4250453230014 |
10 | 1210112020993 |
11 | 427229763137 |
12 | 176640098541 |
13 | 8a161567395 |
14 | 427d94cb161 |
15 | 21727824dcd |
hex | 119c04c1201 |
1210112020993 has 2 divisors, whose sum is σ = 1210112020994. Its totient is φ = 1210112020992.
The previous prime is 1210112020991. The next prime is 1210112021051. The reversal of 1210112020993 is 3990202110121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1177806631824 + 32305389169 = 1085268^2 + 179737^2 .
It is a cyclic number.
It is not a de Polignac number, because 1210112020993 - 21 = 1210112020991 is a prime.
It is a super-2 number, since 2×12101120209932 (a number of 25 digits) contains 22 as substring.
Together with 1210112020991, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1210112020991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605056010496 + 605056010497.
It is an arithmetic number, because the mean of its divisors is an integer number (605056010497).
Almost surely, 21210112020993 is an apocalyptic number.
It is an amenable number.
1210112020993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210112020993 is an equidigital number, since it uses as much as digits as its factorization.
1210112020993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 31.
The spelling of 1210112020993 in words is "one trillion, two hundred ten billion, one hundred twelve million, twenty thousand, nine hundred ninety-three".
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