12101135441441 has 4 divisors (see below), whose sum is σ = 12738037306800. Its totient is φ = 11464233576084.

The previous prime is 12101135441407. The next prime is 12101135441453. The reversal of 12101135441441 is 14414453110121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12101135441441 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12101135441398 and 12101135441407.

It is not an unprimeable number, because it can be changed into a prime (12101135441491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318450932651 + ... + 318450932688.

It is an arithmetic number, because the mean of its divisors is an integer number (3184509326700).

Almost surely, 2^{12101135441441} is an apocalyptic number.

It is an amenable number.

12101135441441 is a deficient number, since it is larger than the sum of its proper divisors (636901865359).

12101135441441 is an equidigital number, since it uses as much as digits as its factorization.

12101135441441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 636901865358.

The product of its (nonzero) digits is 7680, while the sum is 32.

Adding to 12101135441441 its reverse (14414453110121), we get a palindrome (26515588551562).

The spelling of 12101135441441 in words is "twelve trillion, one hundred one billion, one hundred thirty-five million, four hundred forty-one thousand, four hundred forty-one".