Search a number
-
+
121012202112013 is a prime number
BaseRepresentation
bin11011100000111101011001…
…010100100000010000001101
3120212110122122102121222100001
4123200331121110200100031
5111330130442220041023
61105212123241004301
734326562115161612
oct3340753124402015
9525418572558301
10121012202112013
1135615a943464a3
12116a4b85783691
13526a52b6a3724
1421c5043ca6509
15decc122626ad
hex6e0f5952040d

121012202112013 has 2 divisors, whose sum is σ = 121012202112014. Its totient is φ = 121012202112012.

The previous prime is 121012202111963. The next prime is 121012202112031. The reversal of 121012202112013 is 310211202210121.

Together with next prime (121012202112031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117710066228329 + 3302135883684 = 10849427^2 + 1817178^2 .

It is a cyclic number.

It is not a de Polignac number, because 121012202112013 - 229 = 121011665241101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121012208112013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60506101056006 + 60506101056007.

It is an arithmetic number, because the mean of its divisors is an integer number (60506101056007).

Almost surely, 2121012202112013 is an apocalyptic number.

It is an amenable number.

121012202112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

121012202112013 is an equidigital number, since it uses as much as digits as its factorization.

121012202112013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 121012202112013 its reverse (310211202210121), we get a palindrome (431223404322134).

The spelling of 121012202112013 in words is "one hundred twenty-one trillion, twelve billion, two hundred two million, one hundred twelve thousand, thirteen".