Base | Representation |
---|---|
bin | 11011100000111101011001… |
… | …110011011001100101100011 |
3 | 120212110122122222212110021212 |
4 | 123200331121303121211203 |
5 | 111330131001303224141 |
6 | 1105212124130340335 |
7 | 34326562244053406 |
oct | 3340753163314543 |
9 | 525418588773255 |
10 | 121012210211171 |
11 | 35615a98978514 |
12 | 116a4b8842a6ab |
13 | 526a53027b026 |
14 | 21c5044db3d3d |
15 | decc12d122eb |
hex | 6e0f59cd9963 |
121012210211171 has 2 divisors, whose sum is σ = 121012210211172. Its totient is φ = 121012210211170.
The previous prime is 121012210211141. The next prime is 121012210211209. The reversal of 121012210211171 is 171112012210121.
It is a weak prime.
It is an emirp because it is prime and its reverse (171112012210121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121012210211171 - 218 = 121012209949027 is a prime.
It is not a weakly prime, because it can be changed into another prime (121012210211131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60506105105585 + 60506105105586.
It is an arithmetic number, because the mean of its divisors is an integer number (60506105105586).
Almost surely, 2121012210211171 is an apocalyptic number.
121012210211171 is a deficient number, since it is larger than the sum of its proper divisors (1).
121012210211171 is an equidigital number, since it uses as much as digits as its factorization.
121012210211171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 23.
Adding to 121012210211171 its reverse (171112012210121), we get a palindrome (292124222421292).
The spelling of 121012210211171 in words is "one hundred twenty-one trillion, twelve billion, two hundred ten million, two hundred eleven thousand, one hundred seventy-one".
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