Base | Representation |
---|---|
bin | 10001100111000000111… |
… | …001110110100000001111 |
3 | 11021200112111102012111121 |
4 | 101213000321312200033 |
5 | 124311312240413403 |
6 | 2323531130301411 |
7 | 153266645664304 |
oct | 21470071664017 |
9 | 4250474365447 |
10 | 1210122201103 |
11 | 427234486652 |
12 | 176643587867 |
13 | 8a1636bcc0a |
14 | 427da9bb0ab |
15 | 217286863bd |
hex | 119c0e7680f |
1210122201103 has 2 divisors, whose sum is σ = 1210122201104. Its totient is φ = 1210122201102.
The previous prime is 1210122201083. The next prime is 1210122201149. The reversal of 1210122201103 is 3011022210121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1210122201103 - 213 = 1210122192911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210122201193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605061100551 + 605061100552.
It is an arithmetic number, because the mean of its divisors is an integer number (605061100552).
Almost surely, 21210122201103 is an apocalyptic number.
1210122201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210122201103 is an equidigital number, since it uses as much as digits as its factorization.
1210122201103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1210122201103 its reverse (3011022210121), we get a palindrome (4221144411224).
The spelling of 1210122201103 in words is "one trillion, two hundred ten billion, one hundred twenty-two million, two hundred one thousand, one hundred three".
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