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12101826113 = 13930909701
BaseRepresentation
bin10110100010101001…
…10011011001000001
31011020101201110111222
423101110303121001
5144241031413423
65320504044425
7605615552606
oct132124633101
934211643458
1012101826113
115150190093
122418a63715
1311ab297570
1482b3666ad
154ac6863c8
hex2d1533641

12101826113 has 4 divisors (see below), whose sum is σ = 13032735828. Its totient is φ = 11170916400.

The previous prime is 12101826109. The next prime is 12101826127. The reversal of 12101826113 is 31162810121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1810332304 + 10291493809 = 42548^2 + 101447^2 .

It is a cyclic number.

It is not a de Polignac number, because 12101826113 - 22 = 12101826109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12101826133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465454838 + ... + 465454863.

It is an arithmetic number, because the mean of its divisors is an integer number (3258183957).

Almost surely, 212101826113 is an apocalyptic number.

12101826113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12101826113 is a deficient number, since it is larger than the sum of its proper divisors (930909715).

12101826113 is an equidigital number, since it uses as much as digits as its factorization.

12101826113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 930909714.

The product of its (nonzero) digits is 576, while the sum is 26.

The spelling of 12101826113 in words is "twelve billion, one hundred one million, eight hundred twenty-six thousand, one hundred thirteen".

Divisors: 1 13 930909701 12101826113