12102011020212 has 24 divisors (see below), whose sum is σ = 28460372376576. Its totient is φ = 4002239864448.

The previous prime is 12102011020201. The next prime is 12102011020223. The reversal of 12102011020212 is 21202011020121.

It is an interprime number because it is at equal distance from previous prime (12102011020201) and next prime (12102011020223).

It is a super-3 number, since 3×12102011020212³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12102011020191 and 12102011020200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3970474533 + ... + 3970477580.

It is an arithmetic number, because the mean of its divisors is an integer number (1185848849024).

Almost surely, 2^{12102011020212} is an apocalyptic number.

12102011020212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12102011020212 is an abundant number, since it is smaller than the sum of its proper divisors (16358361356364).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12102011020212 is a wasteful number, since it uses less digits than its factorization.

12102011020212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7940952247 (or 7940952245 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 12102011020212 its reverse (21202011020121), we get a palindrome (33304022040333).

Subtracting 12102011020212 from its reverse (21202011020121), we obtain a palindrome (9099999999909).

The spelling of 12102011020212 in words is "twelve trillion, one hundred two billion, eleven million, twenty thousand, two hundred twelve".