121020113 has 2 divisors, whose sum is σ = 121020114. Its totient is φ = 121020112.

The previous prime is 121020091. The next prime is 121020131. The reversal of 121020113 is 311020121.

Together with next prime (121020131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119093569 + 1926544 = 10913^2 + 1388^2 .

It is a cyclic number.

It is not a de Polignac number, because 121020113 - 2¹⁶ = 120954577 is a prime.

It is a super-3 number, since 3×121020113³ (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 121020094 and 121020103.

It is not a weakly prime, because it can be changed into another prime (121020143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510056 + 60510057.

It is an arithmetic number, because the mean of its divisors is an integer number (60510057).

Almost surely, 2^121020113 is an apocalyptic number.

It is an amenable number.

121020113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121020113 is an equidigital number, since it uses as much as digits as its factorization.

121020113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 121020113 is about 11000.9141892845. The cubic root of 121020113 is about 494.6361479462.

Adding to 121020113 its reverse (311020121), we get a palindrome (432040234).

The spelling of 121020113 in words is "one hundred twenty-one million, twenty thousand, one hundred thirteen".