Base | Representation |
---|---|
bin | 111000010110101011… |
… | …1000111101111010001 |
3 | 102120101002201002002022 |
4 | 1300231113013233101 |
5 | 3440322122320032 |
6 | 131332413101225 |
7 | 11512664022146 |
oct | 1605527075721 |
9 | 376332632068 |
10 | 121020120017 |
11 | 47362780415 |
12 | 1b555487815 |
13 | b54864a494 |
14 | 5c00a103cd |
15 | 323480d512 |
hex | 1c2d5c7bd1 |
121020120017 has 2 divisors, whose sum is σ = 121020120018. Its totient is φ = 121020120016.
The previous prime is 121020119971. The next prime is 121020120049. The reversal of 121020120017 is 710021020121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 83403129616 + 37616990401 = 288796^2 + 193951^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121020120017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121020119977 and 121020120004.
It is not a weakly prime, because it can be changed into another prime (121020120317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510060008 + 60510060009.
It is an arithmetic number, because the mean of its divisors is an integer number (60510060009).
Almost surely, 2121020120017 is an apocalyptic number.
It is an amenable number.
121020120017 is a deficient number, since it is larger than the sum of its proper divisors (1).
121020120017 is an equidigital number, since it uses as much as digits as its factorization.
121020120017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 121020120017 its reverse (710021020121), we get a palindrome (831041140138).
The spelling of 121020120017 in words is "one hundred twenty-one billion, twenty million, one hundred twenty thousand, seventeen".
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