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121020120017 is a prime number
BaseRepresentation
bin111000010110101011…
…1000111101111010001
3102120101002201002002022
41300231113013233101
53440322122320032
6131332413101225
711512664022146
oct1605527075721
9376332632068
10121020120017
1147362780415
121b555487815
13b54864a494
145c00a103cd
15323480d512
hex1c2d5c7bd1

121020120017 has 2 divisors, whose sum is σ = 121020120018. Its totient is φ = 121020120016.

The previous prime is 121020119971. The next prime is 121020120049. The reversal of 121020120017 is 710021020121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83403129616 + 37616990401 = 288796^2 + 193951^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121020120017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121020119977 and 121020120004.

It is not a weakly prime, because it can be changed into another prime (121020120317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510060008 + 60510060009.

It is an arithmetic number, because the mean of its divisors is an integer number (60510060009).

Almost surely, 2121020120017 is an apocalyptic number.

It is an amenable number.

121020120017 is a deficient number, since it is larger than the sum of its proper divisors (1).

121020120017 is an equidigital number, since it uses as much as digits as its factorization.

121020120017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 17.

Adding to 121020120017 its reverse (710021020121), we get a palindrome (831041140138).

The spelling of 121020120017 in words is "one hundred twenty-one billion, twenty million, one hundred twenty thousand, seventeen".