Base | Representation |
---|---|
bin | 11011100001000100110001… |
… | …010001001110110011001011 |
3 | 120212111102002020201102221222 |
4 | 123201010301101032303023 |
5 | 111330243201221200133 |
6 | 1105215513050552255 |
7 | 34330262252026043 |
oct | 3341046121166313 |
9 | 525442066642858 |
10 | 121020120100043 |
11 | 3561938789905a |
12 | 116a661543868b |
13 | 526b1c0c30748 |
14 | 21c5595702723 |
15 | ded02745ce98 |
hex | 6e113144eccb |
121020120100043 has 2 divisors, whose sum is σ = 121020120100044. Its totient is φ = 121020120100042.
The previous prime is 121020120100039. The next prime is 121020120100129. The reversal of 121020120100043 is 340001021020121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121020120100043 - 22 = 121020120100039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121020120099994 and 121020120100030.
It is not a weakly prime, because it can be changed into another prime (121020126100043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510060050021 + 60510060050022.
It is an arithmetic number, because the mean of its divisors is an integer number (60510060050022).
Almost surely, 2121020120100043 is an apocalyptic number.
121020120100043 is a deficient number, since it is larger than the sum of its proper divisors (1).
121020120100043 is an equidigital number, since it uses as much as digits as its factorization.
121020120100043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 121020120100043 its reverse (340001021020121), we get a palindrome (461021141120164).
The spelling of 121020120100043 in words is "one hundred twenty-one trillion, twenty billion, one hundred twenty million, one hundred thousand, forty-three".
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