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121020199997 is a prime number
BaseRepresentation
bin111000010110101011…
…1011011010000111101
3102120101002212010210112
41300231113123100331
53440322132344442
6131332414515405
711512664504264
oct1605527332075
9376332763715
10121020199997
1147362825514
121b555505b65
13b5486779c8
145c00a315db
153234827082
hex1c2d5db43d

121020199997 has 2 divisors, whose sum is σ = 121020199998. Its totient is φ = 121020199996.

The previous prime is 121020199987. The next prime is 121020200023. The reversal of 121020199997 is 799991020121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100172883001 + 20847316996 = 316501^2 + 144386^2 .

It is an emirp because it is prime and its reverse (799991020121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121020199997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121020199907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510099998 + 60510099999.

It is an arithmetic number, because the mean of its divisors is an integer number (60510099999).

Almost surely, 2121020199997 is an apocalyptic number.

It is an amenable number.

121020199997 is a deficient number, since it is larger than the sum of its proper divisors (1).

121020199997 is an equidigital number, since it uses as much as digits as its factorization.

121020199997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 183708, while the sum is 50.

The spelling of 121020199997 in words is "one hundred twenty-one billion, twenty million, one hundred ninety-nine thousand, nine hundred ninety-seven".