12102033311131 has 4 divisors (see below), whose sum is σ = 12107685827664. Its totient is φ = 12096380794600.

The previous prime is 12102033311129. The next prime is 12102033311153. The reversal of 12102033311131 is 13111333020121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12102033311131 - 2¹ = 12102033311129 is a prime.

It is a super-2 number, since 2×12102033311131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12102033411131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2826255055 + ... + 2826259336.

It is an arithmetic number, because the mean of its divisors is an integer number (3026921456916).

Almost surely, 2^{12102033311131} is an apocalyptic number.

12102033311131 is a deficient number, since it is larger than the sum of its proper divisors (5652516533).

12102033311131 is an equidigital number, since it uses as much as digits as its factorization.

12102033311131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5652516532.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 12102033311131 its reverse (13111333020121), we get a palindrome (25213366331252).

The spelling of 12102033311131 in words is "twelve trillion, one hundred two billion, thirty-three million, three hundred eleven thousand, one hundred thirty-one".