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121021009937 is a prime number
BaseRepresentation
bin111000010110101101…
…0100001000000010001
3102120101011101021211022
41300231122201000101
53440322334304222
6131332444125225
711513004416522
oct1605532410021
9376334337738
10121021009937
1147363228a93
121b555836815
13b54889c569
145c00ba2849
153234937042
hex1c2d6a1011

121021009937 has 2 divisors, whose sum is σ = 121021009938. Its totient is φ = 121021009936.

The previous prime is 121021009933. The next prime is 121021009939. The reversal of 121021009937 is 739900120121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91697529856 + 29323480081 = 302816^2 + 171241^2 .

It is an emirp because it is prime and its reverse (739900120121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121021009937 - 22 = 121021009933 is a prime.

Together with 121021009939, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 121021009897 and 121021009906.

It is not a weakly prime, because it can be changed into another prime (121021009933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510504968 + 60510504969.

It is an arithmetic number, because the mean of its divisors is an integer number (60510504969).

Almost surely, 2121021009937 is an apocalyptic number.

It is an amenable number.

121021009937 is a deficient number, since it is larger than the sum of its proper divisors (1).

121021009937 is an equidigital number, since it uses as much as digits as its factorization.

121021009937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804, while the sum is 35.

The spelling of 121021009937 in words is "one hundred twenty-one billion, twenty-one million, nine thousand, nine hundred thirty-seven".