Base | Representation |
---|---|
bin | 10001100111000110001… |
… | …110001111101010001100 |
3 | 11021200202201022122210101 |
4 | 101213012032033222030 |
5 | 124312003111324400 |
6 | 2323544035020444 |
7 | 153302111311015 |
oct | 21470616175214 |
9 | 4250681278711 |
10 | 1210211433100 |
11 | 42727a8929aa |
12 | 17666943a724 |
13 | 8a179033407 |
14 | 428087a800c |
15 | 2173141056a |
hex | 119c638fa8c |
1210211433100 has 18 divisors (see below), whose sum is σ = 2626158810044. Its totient is φ = 484084573200.
The previous prime is 1210211433019. The next prime is 1210211433103. The reversal of 1210211433100 is 13341120121.
It is a super-2 number, since 2×12102114331002 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1210211433103) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6051057066 + ... + 6051057265.
Almost surely, 21210211433100 is an apocalyptic number.
1210211433100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1210211433100 is an abundant number, since it is smaller than the sum of its proper divisors (1415947376944).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1210211433100 is a wasteful number, since it uses less digits than its factorization.
1210211433100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12102114345 (or 12102114338 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1210211433100 its reverse (13341120121), we get a palindrome (1223552553221).
The spelling of 1210211433100 in words is "one trillion, two hundred ten billion, two hundred eleven million, four hundred thirty-three thousand, one hundred".
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