Base | Representation |
---|---|
bin | 1011000000011100010010… |
… | …1101110100110111000111 |
3 | 1120211221221202002201202211 |
4 | 2300013010231310313013 |
5 | 3041240323121021132 |
6 | 41423403512244251 |
7 | 2356233242030323 |
oct | 260070455646707 |
9 | 46757852081684 |
10 | 12102223220167 |
11 | 394658455a143 |
12 | 14355aa0a0687 |
13 | 69a3089a0a02 |
14 | 2dba72002983 |
15 | 15ec17412147 |
hex | b01c4b74dc7 |
12102223220167 has 2 divisors, whose sum is σ = 12102223220168. Its totient is φ = 12102223220166.
The previous prime is 12102223220119. The next prime is 12102223220173. The reversal of 12102223220167 is 76102232220121.
12102223220167 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12102223220167 - 215 = 12102223187399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12102223224167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051111610083 + 6051111610084.
It is an arithmetic number, because the mean of its divisors is an integer number (6051111610084).
Almost surely, 212102223220167 is an apocalyptic number.
12102223220167 is a deficient number, since it is larger than the sum of its proper divisors (1).
12102223220167 is an equidigital number, since it uses as much as digits as its factorization.
12102223220167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 12102223220167 its reverse (76102232220121), we get a palindrome (88204455440288).
The spelling of 12102223220167 in words is "twelve trillion, one hundred two billion, two hundred twenty-three million, two hundred twenty thousand, one hundred sixty-seven".
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