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1210231002521 is a prime number
BaseRepresentation
bin10001100111000111011…
…000111001010110011001
311021200211002010212222202
4101213013120321112121
5124312023114040041
62323550014255545
7153302436534512
oct21470730712631
94250732125882
101210231002521
1142728a939782
12176673ab75b5
138a1800c5858
144280b21da09
1521732ec8a9b
hex119c7639599

1210231002521 has 2 divisors, whose sum is σ = 1210231002522. Its totient is φ = 1210231002520.

The previous prime is 1210231002517. The next prime is 1210231002523. The reversal of 1210231002521 is 1252001320121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 698954521225 + 511276481296 = 836035^2 + 715036^2 .

It is a cyclic number.

It is not a de Polignac number, because 1210231002521 - 22 = 1210231002517 is a prime.

Together with 1210231002523, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1210231002493 and 1210231002502.

It is not a weakly prime, because it can be changed into another prime (1210231002523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605115501260 + 605115501261.

It is an arithmetic number, because the mean of its divisors is an integer number (605115501261).

Almost surely, 21210231002521 is an apocalyptic number.

It is an amenable number.

1210231002521 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210231002521 is an equidigital number, since it uses as much as digits as its factorization.

1210231002521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 1210231002521 its reverse (1252001320121), we get a palindrome (2462232322642).

The spelling of 1210231002521 in words is "one trillion, two hundred ten billion, two hundred thirty-one million, two thousand, five hundred twenty-one".