Base | Representation |
---|---|
bin | 11011100001000111100101… |
… | …011101000011111111110011 |
3 | 120212111200212221000202212021 |
4 | 123201013211131003333303 |
5 | 111330320344113203103 |
6 | 1105221133040212311 |
7 | 34330430210065135 |
oct | 3341074535037763 |
9 | 525450787022767 |
10 | 121023143100403 |
11 | 3561a699238a65 |
12 | 116a711990a097 |
13 | 526b583308c5b |
14 | 21c57a0db5055 |
15 | ded152a46bbd |
hex | 6e11e5743ff3 |
121023143100403 has 2 divisors, whose sum is σ = 121023143100404. Its totient is φ = 121023143100402.
The previous prime is 121023143100401. The next prime is 121023143100443. The reversal of 121023143100403 is 304001341320121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121023143100403 - 21 = 121023143100401 is a prime.
Together with 121023143100401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (121023143100401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60511571550201 + 60511571550202.
It is an arithmetic number, because the mean of its divisors is an integer number (60511571550202).
Almost surely, 2121023143100403 is an apocalyptic number.
121023143100403 is a deficient number, since it is larger than the sum of its proper divisors (1).
121023143100403 is an equidigital number, since it uses as much as digits as its factorization.
121023143100403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 121023143100403 its reverse (304001341320121), we get a palindrome (425024484420524).
The spelling of 121023143100403 in words is "one hundred twenty-one trillion, twenty-three billion, one hundred forty-three million, one hundred thousand, four hundred three".
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