Base | Representation |
---|---|
bin | 10001100111001011100… |
… | …111110100100111000100 |
3 | 11021201000000210011022210 |
4 | 101213023213310213010 |
5 | 124312144304233012 |
6 | 2324001032423420 |
7 | 153304261314555 |
oct | 21471347644704 |
9 | 4251000704283 |
10 | 1210302024132 |
11 | 427316a38323 |
12 | 176693847b70 |
13 | 8a191a31386 |
14 | 4281682a32c |
15 | 2173935723c |
hex | 119cb9f49c4 |
1210302024132 has 12 divisors (see below), whose sum is σ = 2824038056336. Its totient is φ = 403434008040.
The previous prime is 1210302024103. The next prime is 1210302024133. The reversal of 1210302024132 is 2314202030121.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 1210302024099 and 1210302024108.
It is not an unprimeable number, because it can be changed into a prime (1210302024133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50429250994 + ... + 50429251017.
Almost surely, 21210302024132 is an apocalyptic number.
1210302024132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1210302024132 is an abundant number, since it is smaller than the sum of its proper divisors (1613736032204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1210302024132 is a wasteful number, since it uses less digits than its factorization.
1210302024132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100858502018 (or 100858502016 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 1210302024132 its reverse (2314202030121), we get a palindrome (3524504054253).
The spelling of 1210302024132 in words is "one trillion, two hundred ten billion, three hundred two million, twenty-four thousand, one hundred thirty-two".
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