Base | Representation |
---|---|
bin | 1011000000011111010000… |
… | …1110100010000111101111 |
3 | 1120212001000021222202201111 |
4 | 2300013310032202013233 |
5 | 3041243441200321221 |
6 | 41424014545052451 |
7 | 2356262061220231 |
oct | 260076416420757 |
9 | 46761007882644 |
10 | 12103020323311 |
11 | 39469534a1575 |
12 | 1435791027127 |
13 | 69a404b7b188 |
14 | 2dbb09c16251 |
15 | 15ec623b5be1 |
hex | b01f43a21ef |
12103020323311 has 2 divisors, whose sum is σ = 12103020323312. Its totient is φ = 12103020323310.
The previous prime is 12103020323291. The next prime is 12103020323353. The reversal of 12103020323311 is 11332302030121.
12103020323311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12103020323311 - 217 = 12103020192239 is a prime.
It is a super-3 number, since 3×121030203233113 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12103020333311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051510161655 + 6051510161656.
It is an arithmetic number, because the mean of its divisors is an integer number (6051510161656).
Almost surely, 212103020323311 is an apocalyptic number.
12103020323311 is a deficient number, since it is larger than the sum of its proper divisors (1).
12103020323311 is an equidigital number, since it uses as much as digits as its factorization.
12103020323311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 12103020323311 its reverse (11332302030121), we get a palindrome (23435322353432).
The spelling of 12103020323311 in words is "twelve trillion, one hundred three billion, twenty million, three hundred twenty-three thousand, three hundred eleven".
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