Base | Representation |
---|---|
bin | 1011000000011111010011… |
… | …0111010011011111100111 |
3 | 1120212001001001002202220001 |
4 | 2300013310313103133213 |
5 | 3041244001414330203 |
6 | 41424020010122131 |
7 | 2356262251113451 |
oct | 260076467233747 |
9 | 46761031082801 |
10 | 12103031011303 |
11 | 3946959531621 |
12 | 1435794720347 |
13 | 69a407150c2b |
14 | 2dbb0b3d92d1 |
15 | 15ec632c791d |
hex | b01f4dd37e7 |
12103031011303 has 4 divisors (see below), whose sum is σ = 12103178276848. Its totient is φ = 12102883745760.
The previous prime is 12103031011193. The next prime is 12103031011321. The reversal of 12103031011303 is 30311013030121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12103031011303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12103031011333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73509426 + ... + 73673887.
It is an arithmetic number, because the mean of its divisors is an integer number (3025794569212).
Almost surely, 212103031011303 is an apocalyptic number.
12103031011303 is a deficient number, since it is larger than the sum of its proper divisors (147265545).
12103031011303 is an equidigital number, since it uses as much as digits as its factorization.
12103031011303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 147265544.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 12103031011303 its reverse (30311013030121), we get a palindrome (42414044041424).
The spelling of 12103031011303 in words is "twelve trillion, one hundred three billion, thirty-one million, eleven thousand, three hundred three".
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