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12103110433 is a prime number
BaseRepresentation
bin10110100010110011…
…01100111100100001
31011020111010201021101
423101121230330201
5144241344013213
65320551354401
7605632512151
oct132131547441
934214121241
1012103110433
115150988007
122419382a01
1311ab62700b
1482b5bc761
154ac83bbdd
hex2d166cf21

12103110433 has 2 divisors, whose sum is σ = 12103110434. Its totient is φ = 12103110432.

The previous prime is 12103110359. The next prime is 12103110451. The reversal of 12103110433 is 33401130121.

12103110433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7602444864 + 4500665569 = 87192^2 + 67087^2 .

It is a cyclic number.

It is not a de Polignac number, because 12103110433 - 225 = 12069556001 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12103110433.

It is not a weakly prime, because it can be changed into another prime (12103110463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051555216 + 6051555217.

It is an arithmetic number, because the mean of its divisors is an integer number (6051555217).

Almost surely, 212103110433 is an apocalyptic number.

It is an amenable number.

12103110433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12103110433 is an equidigital number, since it uses as much as digits as its factorization.

12103110433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12103110433 its reverse (33401130121), we get a palindrome (45504240554).

The spelling of 12103110433 in words is "twelve billion, one hundred three million, one hundred ten thousand, four hundred thirty-three".