Base | Representation |
---|---|
bin | 10110100010110100… |
… | …00011111001110111 |
3 | 1011020111022111021021 |
4 | 23101122003321313 |
5 | 144241410020341 |
6 | 5320553402011 |
7 | 605633353261 |
oct | 132132037167 |
9 | 34214274237 |
10 | 12103204471 |
11 | 5150a41726 |
12 | 2419409307 |
13 | 11ab65aa67 |
14 | 82b604b31 |
15 | 4ac8599d1 |
hex | 2d1683e77 |
12103204471 has 2 divisors, whose sum is σ = 12103204472. Its totient is φ = 12103204470.
The previous prime is 12103204447. The next prime is 12103204493. The reversal of 12103204471 is 17440230121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12103204471 - 213 = 12103196279 is a prime.
It is a super-3 number, since 3×121032044713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12103204271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051602235 + 6051602236.
It is an arithmetic number, because the mean of its divisors is an integer number (6051602236).
Almost surely, 212103204471 is an apocalyptic number.
12103204471 is a deficient number, since it is larger than the sum of its proper divisors (1).
12103204471 is an equidigital number, since it uses as much as digits as its factorization.
12103204471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 12103204471 its reverse (17440230121), we get a palindrome (29543434592).
The spelling of 12103204471 in words is "twelve billion, one hundred three million, two hundred four thousand, four hundred seventy-one".
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