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1210333231213 is a prime number
BaseRepresentation
bin10001100111001101011…
…110110111100001101101
311021201002012111122101121
4101213031132313201231
5124312230301344323
62324004105340541
7153305120501401
oct21471536674155
94251065448347
101210333231213
114273326126a7
121766a2197751
138a1983398c2
144281aa31101
152173be6da5d
hex119cd7b786d

1210333231213 has 2 divisors, whose sum is σ = 1210333231214. Its totient is φ = 1210333231212.

The previous prime is 1210333231199. The next prime is 1210333231243. The reversal of 1210333231213 is 3121323330121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1136394376324 + 73938854889 = 1066018^2 + 271917^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1210333231213 is a prime.

It is a super-4 number, since 4×12103332312134 (a number of 49 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1210333231243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605166615606 + 605166615607.

It is an arithmetic number, because the mean of its divisors is an integer number (605166615607).

Almost surely, 21210333231213 is an apocalyptic number.

It is an amenable number.

1210333231213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210333231213 is an equidigital number, since it uses as much as digits as its factorization.

1210333231213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1210333231213 its reverse (3121323330121), we get a palindrome (4331656561334).

The spelling of 1210333231213 in words is "one trillion, two hundred ten billion, three hundred thirty-three million, two hundred thirty-one thousand, two hundred thirteen".