Base | Representation |
---|---|
bin | 10110100010111010… |
… | …01001010111111011 |
3 | 1011020112211120210011 |
4 | 23101131021113323 |
5 | 144242111411212 |
6 | 5321023002351 |
7 | 605643262351 |
oct | 132135112773 |
9 | 34215746704 |
10 | 12104013307 |
11 | 5151444391 |
12 | 24197393b7 |
13 | 11ab881c69 |
14 | 82b7757d1 |
15 | 4ac9694a7 |
hex | 2d17495fb |
12104013307 has 2 divisors, whose sum is σ = 12104013308. Its totient is φ = 12104013306.
The previous prime is 12104013293. The next prime is 12104013347. The reversal of 12104013307 is 70331040121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12104013307 - 27 = 12104013179 is a prime.
It is a super-3 number, since 3×121040133073 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12104013347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052006653 + 6052006654.
It is an arithmetic number, because the mean of its divisors is an integer number (6052006654).
Almost surely, 212104013307 is an apocalyptic number.
12104013307 is a deficient number, since it is larger than the sum of its proper divisors (1).
12104013307 is an equidigital number, since it uses as much as digits as its factorization.
12104013307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 12104013307 its reverse (70331040121), we get a palindrome (82435053428).
The spelling of 12104013307 in words is "twelve billion, one hundred four million, thirteen thousand, three hundred seven".
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