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12104013347 is a prime number
BaseRepresentation
bin10110100010111010…
…01001011000100011
31011020112211120211122
423101131021120203
5144242111411342
65321023002455
7605643262436
oct132135113043
934215746748
1012104013347
115151444418
12241973942b
1311ab881c9a
1482b77581d
154ac9694d2
hex2d1749623

12104013347 has 2 divisors, whose sum is σ = 12104013348. Its totient is φ = 12104013346.

The previous prime is 12104013307. The next prime is 12104013349. The reversal of 12104013347 is 74331040121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12104013347 - 214 = 12103996963 is a prime.

Together with 12104013349, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12104013349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052006673 + 6052006674.

It is an arithmetic number, because the mean of its divisors is an integer number (6052006674).

Almost surely, 212104013347 is an apocalyptic number.

12104013347 is a deficient number, since it is larger than the sum of its proper divisors (1).

12104013347 is an equidigital number, since it uses as much as digits as its factorization.

12104013347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 12104013347 its reverse (74331040121), we get a palindrome (86435053468).

The spelling of 12104013347 in words is "twelve billion, one hundred four million, thirteen thousand, three hundred forty-seven".