Base | Representation |
---|---|
bin | 10001100111010010110… |
… | …000000000101110011001 |
3 | 11021201022100210211020111 |
4 | 101213102300000232121 |
5 | 124312420413031132 |
6 | 2324020543524321 |
7 | 153310242636544 |
oct | 21472260005631 |
9 | 4251270724214 |
10 | 1210421611417 |
11 | 427378497a97 |
12 | 1767078b96a1 |
13 | 8a1b0742495 |
14 | 4282867985b |
15 | 21744aca647 |
hex | 119d2c00b99 |
1210421611417 has 2 divisors, whose sum is σ = 1210421611418. Its totient is φ = 1210421611416.
The previous prime is 1210421611411. The next prime is 1210421611507. The reversal of 1210421611417 is 7141161240121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1171035636736 + 39385974681 = 1082144^2 + 198459^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1210421611417 is a prime.
It is not a weakly prime, because it can be changed into another prime (1210421611411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605210805708 + 605210805709.
It is an arithmetic number, because the mean of its divisors is an integer number (605210805709).
Almost surely, 21210421611417 is an apocalyptic number.
It is an amenable number.
1210421611417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210421611417 is an equidigital number, since it uses as much as digits as its factorization.
1210421611417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 31.
Adding to 1210421611417 its reverse (7141161240121), we get a palindrome (8351582851538).
The spelling of 1210421611417 in words is "one trillion, two hundred ten billion, four hundred twenty-one million, six hundred eleven thousand, four hundred seventeen".
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