Base | Representation |
---|---|
bin | 11011100001011001010110… |
… | …001010110010010110001111 |
3 | 120212120112010000022001121020 |
4 | 123201121112022302112033 |
5 | 111331123423241112421 |
6 | 1105234005300005223 |
7 | 34332003621100401 |
oct | 3341312612622617 |
9 | 525515100261536 |
10 | 121042214004111 |
11 | 35627795272204 |
12 | 116aa960690813 |
13 | 527030237066a |
14 | 21c668db28b71 |
15 | ded8bbe39dc6 |
hex | 6e16562b258f |
121042214004111 has 4 divisors (see below), whose sum is σ = 161389618672152. Its totient is φ = 80694809336072.
The previous prime is 121042214004109. The next prime is 121042214004199. The reversal of 121042214004111 is 111400412240121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 121042214004111 - 21 = 121042214004109 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121042214024111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20173702334016 + ... + 20173702334021.
It is an arithmetic number, because the mean of its divisors is an integer number (40347404668038).
Almost surely, 2121042214004111 is an apocalyptic number.
121042214004111 is a deficient number, since it is larger than the sum of its proper divisors (40347404668041).
121042214004111 is an equidigital number, since it uses as much as digits as its factorization.
121042214004111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40347404668040.
The product of its (nonzero) digits is 512, while the sum is 24.
Adding to 121042214004111 its reverse (111400412240121), we get a palindrome (232442626244232).
The spelling of 121042214004111 in words is "one hundred twenty-one trillion, forty-two billion, two hundred fourteen million, four thousand, one hundred eleven".
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