Base | Representation |
---|---|
bin | 10001100111010010110… |
… | …101101101001000011111 |
3 | 11021201022110121122201111 |
4 | 101213102311231020133 |
5 | 124312421303312111 |
6 | 2324021035522451 |
7 | 153310261424311 |
oct | 21472265551037 |
9 | 4251273548644 |
10 | 1210423104031 |
11 | 427379317459 |
12 | 1767082b9427 |
13 | 8a1b0b4599b |
14 | 428289477b1 |
15 | 21744cc2a21 |
hex | 119d2d6d21f |
1210423104031 has 2 divisors, whose sum is σ = 1210423104032. Its totient is φ = 1210423104030.
The previous prime is 1210423104019. The next prime is 1210423104091. The reversal of 1210423104031 is 1304013240121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1210423104031 - 25 = 1210423103999 is a prime.
It is a super-2 number, since 2×12104231040312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1210423103993 and 1210423104011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210423104001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605211552015 + 605211552016.
It is an arithmetic number, because the mean of its divisors is an integer number (605211552016).
Almost surely, 21210423104031 is an apocalyptic number.
1210423104031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210423104031 is an equidigital number, since it uses as much as digits as its factorization.
1210423104031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 1210423104031 its reverse (1304013240121), we get a palindrome (2514436344152).
The spelling of 1210423104031 in words is "one trillion, two hundred ten billion, four hundred twenty-three million, one hundred four thousand, thirty-one".
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