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121044403314013 is a prime number
BaseRepresentation
bin11011100001011011011000…
…101010010101110101011101
3120212120201202120212112012011
4123201123120222111311131
5111331142414222022023
61105235010424311221
734332112103654164
oct3341333052256535
9525521676775164
10121044403314013
1135628709060133
12116ab271912511
135270590acb2ca
1421c681a7c23db
15ded99924450d
hex6e16d8a95d5d

121044403314013 has 2 divisors, whose sum is σ = 121044403314014. Its totient is φ = 121044403314012.

The previous prime is 121044403313941. The next prime is 121044403314101. The reversal of 121044403314013 is 310413304440121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63651627370809 + 57392775943204 = 7978197^2 + 7575802^2 .

It is a cyclic number.

It is not a de Polignac number, because 121044403314013 - 29 = 121044403313501 is a prime.

It is a super-3 number, since 3×1210444033140133 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121044403312013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60522201657006 + 60522201657007.

It is an arithmetic number, because the mean of its divisors is an integer number (60522201657007).

Almost surely, 2121044403314013 is an apocalyptic number.

It is an amenable number.

121044403314013 is a deficient number, since it is larger than the sum of its proper divisors (1).

121044403314013 is an equidigital number, since it uses as much as digits as its factorization.

121044403314013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 121044403314013 its reverse (310413304440121), we get a palindrome (431457707754134).

The spelling of 121044403314013 in words is "one hundred twenty-one trillion, forty-four billion, four hundred three million, three hundred fourteen thousand, thirteen".