1211000113 has 4 divisors (see below), whose sum is σ = 1213616128. Its totient is φ = 1208384100.

The previous prime is 1211000081. The next prime is 1211000159. The reversal of 1211000113 is 3110001121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1211000113 - 2⁵ = 1211000081 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1211000113.

It is not an unprimeable number, because it can be changed into a prime (1211003113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1307313 + ... + 1308238.

It is an arithmetic number, because the mean of its divisors is an integer number (303404032).

Almost surely, 2^1211000113 is an apocalyptic number.

It is an amenable number.

1211000113 is a deficient number, since it is larger than the sum of its proper divisors (2616015).

1211000113 is an equidigital number, since it uses as much as digits as its factorization.

1211000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2616014.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 1211000113 is about 34799.4269062006. The cubic root of 1211000113 is about 1065.8957434233.

Adding to 1211000113 its reverse (3110001121), we get a palindrome (4321001234).

The spelling of 1211000113 in words is "one billion, two hundred eleven million, one hundred thirteen", and thus it is an aban number.