Base | Representation |
---|---|
bin | 111000011001000100… |
… | …0001110001001110101 |
3 | 102120120200012111021210 |
4 | 1300302020032021311 |
5 | 3441003111201323 |
6 | 131344351232033 |
7 | 11514654603441 |
oct | 1606210161165 |
9 | 376520174253 |
10 | 121100100213 |
11 | 473a3938754 |
12 | 1b578218619 |
13 | b55c0a1841 |
14 | 5c0b4ad821 |
15 | 323b85b293 |
hex | 1c3220e275 |
121100100213 has 4 divisors (see below), whose sum is σ = 161466800288. Its totient is φ = 80733400140.
The previous prime is 121100100131. The next prime is 121100100223. The reversal of 121100100213 is 312001001121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 312001001121 = 3 ⋅104000333707.
It is not a de Polignac number, because 121100100213 - 229 = 120563229301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121100100223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20183350033 + ... + 20183350038.
It is an arithmetic number, because the mean of its divisors is an integer number (40366700072).
Almost surely, 2121100100213 is an apocalyptic number.
It is an amenable number.
121100100213 is a deficient number, since it is larger than the sum of its proper divisors (40366700075).
121100100213 is an equidigital number, since it uses as much as digits as its factorization.
121100100213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40366700074.
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 121100100213 its reverse (312001001121), we get a palindrome (433101101334).
The spelling of 121100100213 in words is "one hundred twenty-one billion, one hundred million, one hundred thousand, two hundred thirteen".
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