1211001025141 has 2 divisors, whose sum is σ = 1211001025142. Its totient is φ = 1211001025140.

The previous prime is 1211001025127. The next prime is 1211001025181. The reversal of 1211001025141 is 1415201001121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1208889255025 + 2111770116 = 1099495^2 + 45954^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211001025141 - 2¹³ = 1211001016949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211001025111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605500512570 + 605500512571.

It is an arithmetic number, because the mean of its divisors is an integer number (605500512571).

Almost surely, 2^{1211001025141} is an apocalyptic number.

It is an amenable number.

1211001025141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211001025141 is an equidigital number, since it uses as much as digits as its factorization.

1211001025141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 1211001025141 its reverse (1415201001121), we get a palindrome (2626202026262).

The spelling of 1211001025141 in words is "one trillion, two hundred eleven billion, one million, twenty-five thousand, one hundred forty-one".