12110012231323 has 4 divisors (see below), whose sum is σ = 12367672066080. Its totient is φ = 11852352396568.

The previous prime is 12110012231249. The next prime is 12110012231327. The reversal of 12110012231323 is 32313221001121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12110012231323 - 2¹³ = 12110012223131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12110012231294 and 12110012231303.

It is not an unprimeable number, because it can be changed into a prime (12110012231327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128829917308 + ... + 128829917401.

It is an arithmetic number, because the mean of its divisors is an integer number (3091918016520).

Almost surely, 2^{12110012231323} is an apocalyptic number.

12110012231323 is a deficient number, since it is larger than the sum of its proper divisors (257659834757).

12110012231323 is an equidigital number, since it uses as much as digits as its factorization.

12110012231323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 257659834756.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 12110012231323 its reverse (32313221001121), we get a palindrome (44423233232444).

The spelling of 12110012231323 in words is "twelve trillion, one hundred ten billion, twelve million, two hundred thirty-one thousand, three hundred twenty-three".