121100130113 has 2 divisors, whose sum is σ = 121100130114. Its totient is φ = 121100130112.

The previous prime is 121100130061. The next prime is 121100130131. The reversal of 121100130113 is 311031001121.

It is a happy number.

Together with next prime (121100130131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120875819584 + 224310529 = 347672^2 + 14977^2 .

It is a cyclic number.

It is not a de Polignac number, because 121100130113 - 2³⁴ = 103920260929 is a prime.

It is not a weakly prime, because it can be changed into another prime (121100130133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60550065056 + 60550065057.

It is an arithmetic number, because the mean of its divisors is an integer number (60550065057).

Almost surely, 2^121100130113 is an apocalyptic number.

It is an amenable number.

121100130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121100130113 is an equidigital number, since it uses as much as digits as its factorization.

121100130113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 121100130113 its reverse (311031001121), we get a palindrome (432131131234).

The spelling of 121100130113 in words is "one hundred twenty-one billion, one hundred million, one hundred thirty thousand, one hundred thirteen".