Base | Representation |
---|---|
bin | 10001100111110101010… |
… | …011111001001100111011 |
3 | 11021202210202212022211011 |
4 | 101213311103321030323 |
5 | 124320112332140011 |
6 | 2324154255414351 |
7 | 153330513266164 |
oct | 21476523711473 |
9 | 4252722768734 |
10 | 1211001443131 |
11 | 427645820157 |
12 | 176849b243b7 |
13 | 8a2738c917c |
14 | 4288169276b |
15 | 2177a962621 |
hex | 119f54f933b |
1211001443131 has 2 divisors, whose sum is σ = 1211001443132. Its totient is φ = 1211001443130.
The previous prime is 1211001443107. The next prime is 1211001443177. The reversal of 1211001443131 is 1313441001121.
It is a weak prime.
It is an emirp because it is prime and its reverse (1313441001121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1211001443131 - 215 = 1211001410363 is a prime.
It is a super-2 number, since 2×12110014431312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1211001443101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605500721565 + 605500721566.
It is an arithmetic number, because the mean of its divisors is an integer number (605500721566).
Almost surely, 21211001443131 is an apocalyptic number.
1211001443131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211001443131 is an equidigital number, since it uses as much as digits as its factorization.
1211001443131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 1211001443131 its reverse (1313441001121), we get a palindrome (2524442444252).
The spelling of 1211001443131 in words is "one trillion, two hundred eleven billion, one million, four hundred forty-three thousand, one hundred thirty-one".
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