Base | Representation |
---|---|
bin | 11011100010001111010111… |
… | …000100100110111010001111 |
3 | 120212210001210221021220012021 |
4 | 123202033113010212322033 |
5 | 111333101213033020421 |
6 | 1105320400301351011 |
7 | 34336126061226604 |
oct | 3342172704467217 |
9 | 525701727256167 |
10 | 121100211220111 |
11 | 3564a347180a82 |
12 | 116ba047868467 |
13 | 5275915bba256 |
14 | 21c93d25da6ab |
15 | e0016392a341 |
hex | 6e23d7126e8f |
121100211220111 has 2 divisors, whose sum is σ = 121100211220112. Its totient is φ = 121100211220110.
The previous prime is 121100211220069. The next prime is 121100211220123. The reversal of 121100211220111 is 111022112001121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121100211220111 - 27 = 121100211219983 is a prime.
It is a super-2 number, since 2×1211002112201112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121100211229111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60550105610055 + 60550105610056.
It is an arithmetic number, because the mean of its divisors is an integer number (60550105610056).
Almost surely, 2121100211220111 is an apocalyptic number.
121100211220111 is a deficient number, since it is larger than the sum of its proper divisors (1).
121100211220111 is an equidigital number, since it uses as much as digits as its factorization.
121100211220111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 16.
Adding to 121100211220111 its reverse (111022112001121), we get a palindrome (232122323221232).
The spelling of 121100211220111 in words is "one hundred twenty-one trillion, one hundred billion, two hundred eleven million, two hundred twenty thousand, one hundred eleven".
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