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121100234143 = 717300033449
BaseRepresentation
bin111000011001000100…
…0101110110110011111
3102120120200110022000011
41300302020232312133
53441003124443033
6131344354144051
711514656002060
oct1606210566637
9376520408004
10121100234143
11473a3a1a339
121b578282027
13b55c11a7a5
145c0b506567
15323b885ccd
hex1c3222ed9f

121100234143 has 4 divisors (see below), whose sum is σ = 138400267600. Its totient is φ = 103800200688.

The previous prime is 121100234117. The next prime is 121100234161. The reversal of 121100234143 is 341432001121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341432001121 = 1907111790311.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121100234143 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121100234113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8650016718 + ... + 8650016731.

It is an arithmetic number, because the mean of its divisors is an integer number (34600066900).

Almost surely, 2121100234143 is an apocalyptic number.

121100234143 is a deficient number, since it is larger than the sum of its proper divisors (17300033457).

121100234143 is an equidigital number, since it uses as much as digits as its factorization.

121100234143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17300033456.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 121100234143 its reverse (341432001121), we get a palindrome (462532235264).

The spelling of 121100234143 in words is "one hundred twenty-one billion, one hundred million, two hundred thirty-four thousand, one hundred forty-three".

Divisors: 1 7 17300033449 121100234143