121100397343 has 2 divisors, whose sum is σ = 121100397344. Its totient is φ = 121100397342.

The previous prime is 121100397317. The next prime is 121100397367. The reversal of 121100397343 is 343793001121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121100397343 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121100397299 and 121100397308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121100397043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60550198671 + 60550198672.

It is an arithmetic number, because the mean of its divisors is an integer number (60550198672).

Almost surely, 2^121100397343 is an apocalyptic number.

121100397343 is a deficient number, since it is larger than the sum of its proper divisors (1).

121100397343 is an equidigital number, since it uses as much as digits as its factorization.

121100397343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 34.

Adding to 121100397343 its reverse (343793001121), we get a palindrome (464893398464).

The spelling of 121100397343 in words is "one hundred twenty-one billion, one hundred million, three hundred ninety-seven thousand, three hundred forty-three".