Base | Representation |
---|---|
bin | 10110100011101000… |
… | …01000101111100001 |
3 | 1011020222011202220020 |
4 | 23101310020233201 |
5 | 144300132240113 |
6 | 5321400104053 |
7 | 606045433110 |
oct | 132164105741 |
9 | 34228152806 |
10 | 12110040033 |
11 | 5154890353 |
12 | 241b765029 |
13 | 11acbb2180 |
14 | 82c4a3c77 |
15 | 4ad25a023 |
hex | 2d1d08be1 |
12110040033 has 16 divisors (see below), whose sum is σ = 19872886656. Its totient is φ = 6387713280.
The previous prime is 12110040031. The next prime is 12110040037. The reversal of 12110040033 is 33004001121.
It is not a de Polignac number, because 12110040033 - 21 = 12110040031 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 12110039994 and 12110040021.
It is not an unprimeable number, because it can be changed into a prime (12110040031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22179288 + ... + 22179833.
It is an arithmetic number, because the mean of its divisors is an integer number (1242055416).
Almost surely, 212110040033 is an apocalyptic number.
12110040033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12110040033 is a deficient number, since it is larger than the sum of its proper divisors (7762846623).
12110040033 is a wasteful number, since it uses less digits than its factorization.
12110040033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44359144.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 12110040033 its reverse (33004001121), we get a palindrome (45114041154).
The spelling of 12110040033 in words is "twelve billion, one hundred ten million, forty thousand, thirty-three".
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