Base | Representation |
---|---|
bin | 1011000000111001101011… |
… | …0011111011010111100111 |
3 | 1120212201022101200022100101 |
4 | 2300032122303323113213 |
5 | 3041403001142024312 |
6 | 41431150251524531 |
7 | 2356632550346623 |
oct | 260163263732747 |
9 | 46781271608311 |
10 | 12110110111207 |
11 | 39499614a2109 |
12 | 143702b459747 |
13 | 69ac94960644 |
14 | 2dc1bd666183 |
15 | 160029a18a57 |
hex | b039acfb5e7 |
12110110111207 has 2 divisors, whose sum is σ = 12110110111208. Its totient is φ = 12110110111206.
The previous prime is 12110110111193. The next prime is 12110110111237. The reversal of 12110110111207 is 70211101101121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12110110111207 - 215 = 12110110078439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12110110111237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055055055603 + 6055055055604.
It is an arithmetic number, because the mean of its divisors is an integer number (6055055055604).
Almost surely, 212110110111207 is an apocalyptic number.
12110110111207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110110111207 is an equidigital number, since it uses as much as digits as its factorization.
12110110111207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 19.
Adding to 12110110111207 its reverse (70211101101121), we get a palindrome (82321211212328).
The spelling of 12110110111207 in words is "twelve trillion, one hundred ten billion, one hundred ten million, one hundred eleven thousand, two hundred seven".
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