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1211011102117 is a prime number
BaseRepresentation
bin10001100111110101111…
…000101111010110100101
311021202211110001001110101
4101213311320233112211
5124320122320231432
62324155242424101
7153330661345405
oct21476570572645
94252743031411
101211011102117
11427650218093
12176851202031
138a2758cb74b
1442882a88805
152177b71e4e7
hex119f5e2f5a5

1211011102117 has 2 divisors, whose sum is σ = 1211011102118. Its totient is φ = 1211011102116.

The previous prime is 1211011102097. The next prime is 1211011102199. The reversal of 1211011102117 is 7112011101121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 839552545441 + 371458556676 = 916271^2 + 609474^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1211011102117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1211011102094 and 1211011102103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211011162117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605505551058 + 605505551059.

It is an arithmetic number, because the mean of its divisors is an integer number (605505551059).

Almost surely, 21211011102117 is an apocalyptic number.

It is an amenable number.

1211011102117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211011102117 is an equidigital number, since it uses as much as digits as its factorization.

1211011102117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 19.

Adding to 1211011102117 its reverse (7112011101121), we get a palindrome (8323022203238).

The spelling of 1211011102117 in words is "one trillion, two hundred eleven billion, eleven million, one hundred two thousand, one hundred seventeen".