Base | Representation |
---|---|
bin | 10001100111110101111… |
… | …001001001101110000101 |
3 | 11021202211110020112121101 |
4 | 101213311321021232011 |
5 | 124320122332210432 |
6 | 2324155245020101 |
7 | 153330662305312 |
oct | 21476571115605 |
9 | 4252743215541 |
10 | 1211011210117 |
11 | 427650291245 |
12 | 176851254631 |
13 | 8a275938957 |
14 | 42882ab5d09 |
15 | 2177b7414e7 |
hex | 119f5e49b85 |
1211011210117 has 2 divisors, whose sum is σ = 1211011210118. Its totient is φ = 1211011210116.
The previous prime is 1211011210099. The next prime is 1211011210141. The reversal of 1211011210117 is 7110121101121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1198059404481 + 12951805636 = 1094559^2 + 113806^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1211011210117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1211011210094 and 1211011210103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211011210417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605505605058 + 605505605059.
It is an arithmetic number, because the mean of its divisors is an integer number (605505605059).
Almost surely, 21211011210117 is an apocalyptic number.
It is an amenable number.
1211011210117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211011210117 is an equidigital number, since it uses as much as digits as its factorization.
1211011210117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 19.
Adding to 1211011210117 its reverse (7110121101121), we get a palindrome (8321132311238).
The spelling of 1211011210117 in words is "one trillion, two hundred eleven billion, eleven million, two hundred ten thousand, one hundred seventeen".
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