Base | Representation |
---|---|
bin | 1011000000111001101101… |
… | …1010000100111110001011 |
3 | 1120212201100002111101212112 |
4 | 2300032123122010332023 |
5 | 3041403011222041021 |
6 | 41431151250132535 |
7 | 2356633031351525 |
oct | 260163332047613 |
9 | 46781302441775 |
10 | 12110120112011 |
11 | 3949967102939 |
12 | 143703288114b |
13 | 69ac96a5268c |
14 | 2dc1c0b0aa15 |
15 | 16002a841d5b |
hex | b039b684f8b |
12110120112011 has 2 divisors, whose sum is σ = 12110120112012. Its totient is φ = 12110120112010.
The previous prime is 12110120111941. The next prime is 12110120112019. The reversal of 12110120112011 is 11021102101121.
12110120112011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12110120112011 - 214 = 12110120095627 is a prime.
It is not a weakly prime, because it can be changed into another prime (12110120112019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055060056005 + 6055060056006.
It is an arithmetic number, because the mean of its divisors is an integer number (6055060056006).
Almost surely, 212110120112011 is an apocalyptic number.
12110120112011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110120112011 is an equidigital number, since it uses as much as digits as its factorization.
12110120112011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 12110120112011 its reverse (11021102101121), we get a palindrome (23131222213132).
The spelling of 12110120112011 in words is "twelve trillion, one hundred ten billion, one hundred twenty million, one hundred twelve thousand, eleven".
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