Base | Representation |
---|---|
bin | 1011000000111001101110… |
… | …0001101101000010101111 |
3 | 1120212201100020020222011202 |
4 | 2300032123201231002233 |
5 | 3041403012230024101 |
6 | 41431151401040115 |
7 | 2356633054346111 |
oct | 260163341550257 |
9 | 46781306228152 |
10 | 12110122111151 |
11 | 3949968248919 |
12 | 143703348603b |
13 | 69ac972a25bc |
14 | 2dc1c10ab3b1 |
15 | 16002aad936b |
hex | b039b86d0af |
12110122111151 has 2 divisors, whose sum is σ = 12110122111152. Its totient is φ = 12110122111150.
The previous prime is 12110122111093. The next prime is 12110122111189. The reversal of 12110122111151 is 15111122101121.
12110122111151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12110122111151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12110122411151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055061055575 + 6055061055576.
It is an arithmetic number, because the mean of its divisors is an integer number (6055061055576).
Almost surely, 212110122111151 is an apocalyptic number.
12110122111151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110122111151 is an equidigital number, since it uses as much as digits as its factorization.
12110122111151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 20.
Adding to 12110122111151 its reverse (15111122101121), we get a palindrome (27221244212272).
The spelling of 12110122111151 in words is "twelve trillion, one hundred ten billion, one hundred twenty-two million, one hundred eleven thousand, one hundred fifty-one".
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